Respuesta :
Answer:
The enlarged picture will cover 12.5 square inches in the paper.
Step-by-step explanation:
For the original picture, height is [tex]2\frac{1}{2}[/tex] inches and length is [tex]1\frac{1}{4}[/tex] inches.
The height of the enlarged picture is 5 inches.
Suppose, the length of the enlarged picture is [tex]x[/tex] inches.
As he enlarges the picture proportionally, so the equation according to the ratio of height and length will be.......
[tex]\frac{5}{x}=\frac{2\frac{1}{2}}{1\frac{1}{4}}\\ \\ \frac{5}{x}=\frac{\frac{5}{2}}{\frac{5}{4}}\\ \\ \frac{5}{x}=\frac{5\times 4}{2\times 5}\\ \\ \frac{5}{x}=\frac{20}{10}\\ \\ 20x=50\\ \\ x=\frac{50}{20}=\frac{5}{2}=2.5[/tex]
Thus, the length of the enlarged picture is 2.5 inches.
So, the area of the enlarged picture [tex]=(5\times 2.5)sq.inch = 12.5sq.inch[/tex]
