A. Horizontal component: 7.3 m/s
Explanation:
The horizontal component of the velocity is given by:
[tex]v_x = v_0 cos \theta[/tex]
where
[tex]v_0 = 16 m/s[/tex] is the magnitude of the initial velocity
[tex]\theta=63^{\circ}[/tex] is the angle of the initial velocity with respect to the ground
Substituting numbers into the equation, we find
[tex]v_x = (16 m/s) cos 63^{\circ}=7.3 m/s[/tex]
B. Vertical component: 14.3 m/s
Explanation:
The vertical component of the velocity is given by:
[tex]v_y = v_0 sin \theta[/tex]
where
[tex]v_0 = 16 m/s[/tex] is the magnitude of the initial velocity
[tex]\theta=63^{\circ}[/tex] is the angle of the initial velocity with respect to the ground
Substituting numbers into the equation, we find
[tex]v_y = (16 m/s) sin 63^{\circ}=14.3 m/s[/tex]
