Respuesta :

Answer:

  • 78.4%

Explanation:

Just as context, write the chemical equation and the mole ratios

1) Balanced chemical equation:

  • CuO (s) +  H₂SO₄ (aq) → CuSO₄ (aq) + H₂O (l)

2) Therotetical (stoichiometric) mole ratios:

  • 1 mol CuO : 1 mol  H₂SO₄  : 1 mol CuSO₄  : 1 mol H₂O

You can calculate the percent yield from the amount of CuSO₄ obtained and the theoretical yield

3) Percent yield

  • Definition:

         Percent yield = (actual yield / theoretical yield)×100

  • Theoretical yiedl (given): 3.19 moles CuSO₄

  • Actual yield (given): 2.50 moles CuSO₄

  • Calcualtion:

Substitute the values in the formula:

  • Percent yield = (2.50 moles CuSO₄ / 3.19 moles CuSO₄)×100 = 78.4%