Respuesta :
Answer:
[tex]0.11\times 10^{-6}weber[/tex]
Explanation:
We have given number of turns N = 560
Inductance L = 8.9 mH
Current through the coil = 7 mA
Inductance of the coil is given as [tex]L=\frac{N\Phi }{I}[/tex]
Where N is number of turns I is current and [tex]\Phi[/tex] is flux
So [tex]\Phi =\frac{LI}{N}=\frac{8.9\times 10^{-3}\times 7\times 10^{-3}}{560}=0.11\times 10^{-6}weber[/tex]
Answer:
The magnetic flux through the coil is [tex]1.1125\times10^{-7}\ Wb[/tex]
Explanation:
Given that,
Number of turns = 560
Inductance = 8.9 mH
Current = 7.0 mA
We need to calculate the magnetic flux
Using formula for magnetic flux
[tex]L=\dfrac{N\phi}{I}[/tex]
[tex]\phi=\dfrac{LI}{N}[/tex]
Where, L = inductance
I = current
N = number of turns
Put the value into formula
[tex]\phi=\dfrac{8.9\times10^{-3}\times7.0\times10^{-3}}{560}[/tex]
[tex]\phi=1.1125\times10^{-7}\ Wb[/tex]
Hence, The magnetic flux through the coil is [tex]1.1125\times10^{-7}\ Wb[/tex]
