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10. A bullet is moving at a speed of 367 m/s when it embeds into a lump of moist
clay. The bullet penetrates a foe and comes to a stop at a distance of 0.0621m.
Determine the acceleration of the bullet while moving into the clay.

Respuesta :

MathPhys

Answer:

-1.08×10⁶ m/s²

Explanation:

Given:

v₀ = 367 m/s

v = 0 m/s

Δx = 0.0621 m

Find: a

v² = v₀² + 2a (x − x₀)

(0 m/s)² = (367 m/s)² + 2a (0.0621 m)

a = -1.08×10⁶ m/s²

Answer:

1080000 m/s2

Explanation:

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