Answer:
[tex]x = \frac{5}{3}[/tex] and [tex]x = - \frac{5}{3}[/tex]
Step-by-step explanation:
We have to solve the equation [tex]0 = 45x^{2} - 125[/tex]
This is a two degree single variable equation.
As there is only one variable x, so the value of x can be found from the single equation.
Again being a two-degree i.e. quadratic equation it will have two solutions.
Now, [tex]0 = 45x^{2} - 125[/tex]
⇒ [tex]125 = 45x^{2}[/tex]
⇒ [tex]45x^{2} = 125[/tex]
⇒ [tex]x^{2} = \frac{125}{45} = \frac{25}{9}[/tex]
⇒ [tex]x = \sqrt{\frac{25}{9}}[/tex] and [tex]x = - \sqrt{\frac{25}{9}}[/tex]
⇒ [tex]x = \frac{5}{3}[/tex] and [tex]x = - \frac{5}{3}[/tex] (Answer)
