Answer:
[tex]\large \boxed{\text{1.52 g}}[/tex]
Explanation:
1. Calculate the moles of CoF₂ needed
[tex]n = \text{0.100 L} \times \dfrac{\text{0.157 mol}}{\text{1 L}} = \text{0.0157 mol}[/tex]
2. Calculate the mass of CoF₂
[tex]m = \text{0.0157 mol} \times \dfrac{\text{96.93 g}}{\text{1 mol}} = \text{1.52 g}\\\\\text{ The student must measure out $\large \boxed{\textbf{1.52 g}}$ of cobalt(II) fluoride}[/tex]
