Answer:
y = 2
Step-by-step explanation:
Given that y varies inversely as the square of x then the equation relating them is
y = [tex]\frac{k}{x^2}[/tex] ← k is the constant of variation
To find k use the condition y = 2 when x = 4
k = yx² = 2 × 4² = 2 × 16 = 32, thus
y = [tex]\frac{32}{x^2}[/tex] ← equation of variation
When x = 4, then
y = [tex]\frac{32}{4^2}[/tex] = [tex]\frac{32}{16}[/tex] = 2