Answer:
0.65812
Explanation:
m = Mass of suitcase = 16 kg
[tex]\theta[/tex] = Incline angle = 40°
g = Acceleration due to gravity = 9.81 m/s²
a = Acceleration of the block = 1.36 m/s²
f = Frictional force
The normal force is given by
[tex]N=mgcos\theta[/tex]
In x direction
[tex]mgsin\theta-f=ma\\\Rightarrow f=mgsin\theta-ma\\\Rightarrow f=16\times 9.81\times sin40-16\times 1.36\\\Rightarrow f=79.13194\ N[/tex]
Frictional force is given by
[tex]f=\mu N=\mu mgcos\theta\\\Rightarrow \mu=\dfrac{f}{mgcos\theta}\\\Rightarrow \mu=\dfrac{79.13194}{16\times 9.81\times cos40}\\\Rightarrow \mu=0.65812[/tex]
The coefficient of kinetic friction between the suitcase and the ramp is 0.65812
