Answer:
The answer to your question is 0.385 moles of O₂
Explanation:
Data
moles of O₂ = ?
moles of Mg = 0.77
Balanced chemical reaction
2Mg(s) + O₂(g) ⇒ 2MgO (s)
Process
1.- To solve this problem, just use the coefficients of the balanced reaction.
2 moles of Mg ---------------- 1 mol of O₂
0.770 moles of Mg ------------- x
x = (0.770 moles of Mg x 1 mol of O₂) / 2 moles of Mg
x = 0.770 / 2
- Result
x = 0.385 moles of O₂
Answer:
0.385 moles O2 are consumed when 0.770 moles magnesium burns
Explanation:
Step 1: Data given
Number of moles of magnesium = 0.770 moles
Step 2: The balanced equation
2Mg(s) + O2(g) → 2MgO(s)
For 2 moles Mg we need 1 mol O2 to produce 2 moles MgO
For 0.770 moles Mg we need 0.770/2 = 0.385 moles O2
0.385 moles O2 are consumed when 0.770 moles magnesium burns
