For this case we have the following quadratic equation:
[tex]a ^ 2 + 8a-13 = 0[/tex]
Where:
[tex]a = 1\\\b = 8\\c = -13[/tex]
The discriminant is given by:
[tex]d = b ^ 2-4ac\\d = 8 ^ 2-4 (1) (- 13)\\d = 64 + 52\\d = 116[/tex]
[tex]d> 0,[/tex] then we have two different real roots.
We have to, based on the quadratic formula: [tex]\sqrt {116} = \sqrt {4 * 29} = 2 \sqrt {29}[/tex]
Thus, the solution will be irrational.
Answer:
[tex]d = 116[/tex]
Two real solutions
Irrational solutions
