Respuesta :
Explanation:
Formula to calculate the electric potential is as follows.
[tex]V_{A} = \frac{kq_{1}}{\sqrt{2}L} + \frac{kq_{2}}{L}[/tex]
Putting the given values into the above formula as follows.
[tex]V_{A} = \frac{kq_{1}}{\sqrt{2}L} + \frac{kq_{2}}{L}[/tex]
= [tex]\frac{9 \times 10^{9}}{0.25}[\frac{-3.3}{\sqrt{2}} + 4.2] \times 10^{-6}[/tex]
= [tex]6.72 \times 10^{4} V[/tex]
Hence, electric potential at point A is [tex]6.72 \times 10^{4} V[/tex].
Now, the electric potential at point B is as follows.
[tex]V_{B} = \frac{kq_{1}}{L} + \frac{kq_{2}}{\sqrt{2}L}[/tex]
= [tex]\frac{9 \times 10^{9}}{0.25} [-3.3 + \frac{4.2}{\sqrt{2}}] \times 10^{-6}[/tex]
= [tex]-1.19 \times 10^{4} V[/tex]
Hence, electric potential at point B is [tex]-1.19 \times 10^{4} V[/tex].
