Respuesta :
Answer:
[tex]x = 1 \: \: \: \: \: or \: \: \: \: \: \: x = 5[/tex]
Step-by-step explanation:
[tex]x^2-6x+5 = 0 \\ x {}^{2} - 5x - x + 5 = 0 \\ x(x - 5) - 1(x - 5) = 0 \\ (x - 1)(x - 5) = 0 \\ x - 1 = 0 \: \: \: \: \: \: or \: \: \: \: \: \: x - 5 = 0 \\ x = 1 \: \: \: \: or \: \: \: \: \: \: x = 5[/tex]
Solutions: x=1 and x=5
the quadratic formula is -b plus or minus the square root of b^2-4ac, with all of that over 2a. in this instance, a=1, b=-6, and c=5. so, the equation works out to be 6 plus or minus the square root of 36-20, all divided by 2.
the next step is to simplify what’s under the square root. 36-20=16. 16 is a perfect square, so we can take the square root of it. now we have the equation 6 plus or minus 4, all divided by 2.
now we can actually solve. let’s start with doing 6 plus 4, divided by 2. 6 +4= 10, and 10/2 = 5. so one solution is x=5
the next solution can be found with subtraction. 6-4=2, and 2/2 = 1. so the other solution to the quadratic formula is x=1
the quadratic formula is -b plus or minus the square root of b^2-4ac, with all of that over 2a. in this instance, a=1, b=-6, and c=5. so, the equation works out to be 6 plus or minus the square root of 36-20, all divided by 2.
the next step is to simplify what’s under the square root. 36-20=16. 16 is a perfect square, so we can take the square root of it. now we have the equation 6 plus or minus 4, all divided by 2.
now we can actually solve. let’s start with doing 6 plus 4, divided by 2. 6 +4= 10, and 10/2 = 5. so one solution is x=5
the next solution can be found with subtraction. 6-4=2, and 2/2 = 1. so the other solution to the quadratic formula is x=1