Answer:
15 minutes
Step-by-step explanation:
Given:
Speed of a train ( Train A ) = 112 miles per hour.
Speed of another train ( Train B ) = 80 miles per hour.
Question asked:
Traveling at this rate, how long would it take to catch up with another train
( Train B ) 8 miles ahead of Train A.
Solution:
By using : [tex]Distance=Speed\times Time[/tex]
As Train B is 8 miles ahead of Train A means :-
Distance traveled by Train A - Distance traveled by Train B = 8
[tex]112\times t-80\times t=8\\112t-80t=8\\32t=8[/tex]
By dividing both side by 32,
[tex]\frac{32t}{32} =\frac{8}{32}[/tex]
[tex]t=\frac{8}{32} \\t=\frac{1}{4}\ hours[/tex]
Now, converting it into minutes,
1 hour = 60 minutes
[tex]\frac{1}{4}[/tex] = [tex]\frac{1}{4} \times60=15\ minutes[/tex]
Hence, it will take 15 minutes to catch up with train B which is running 8 miles ahead of train A.
