The question is in the attachment

The answer is [tex]\frac{\sqrt{3} }{3}[/tex]
You can get this by plugging in the x and y values and solving
[tex]tan(\frac{\pi }{6} )[/tex] = [tex]\frac{sin(\frac{\pi }{6} )}{cos(\frac{\pi }{6} )}[/tex] = [tex]\frac{\frac{1}{2} }{\frac{\sqrt{3} }{2} }[/tex] = [tex]\frac{1}{\sqrt{3} }[/tex] = [tex]\frac{\sqrt{3} }{3}[/tex]