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The concentration (M) of a methanol solution produced when 0.400 L of a 2.00 M solution was diluted to 0.800 L is __________ M.

Respuesta :

Answer: 1.00 M

Explanation: The problem can be solved using the formula of dilution which is the product of Molarity and volume M1V1= M2V2.

Derive for M2, so the formula will be M2 = M1V1 / M2

M2 = 2.00 M ( 0.400 L ) / 0.800 L

= 1.00 M

Answer:

1.00 M

Explanation:

Got It Correct

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