Assume that the distribution of weights of adult men in the United States is normal with mean 190 pounds and standard deviation 30 pounds. The weight of a randomly selected adult male in the United States marks the start of the 40th percentile. How much does he weigh? Enter a number rounded to two decimal places, e.g. 165.12 not 165.12876. Do not enter the units.

Respuesta :

Answer:

182.41

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 190, \sigma = 30[/tex]

40th percentile

Value of X when Z has a pvalue of 0.4. So X when Z = -0.253.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.253 = \frac{X - 190}{30}[/tex]

[tex]X - 190 = -0.253*30[/tex]

[tex]X = 182.41[/tex]

So the answer is 182.41.