Answer:
The density (d) of a substance is calculated by dividing the mass (m) by the given volume (v). Mathematically,
d = m / v
Substituting the known values,
d = 374 g / (2.2 x 10^3 L) = 0.17 g/L
Thus, the density of the weather balloon is 0.17 g/L.
Explanation: If the cylinders were at 1.00 atm, they would contain 50.00 L each, so at 100.0 atm they contain 5000. L each.
1m
3
=1000L,
So 100.0m
3
=1.000×10
5
L.
Since the pressure in the balloon is only 0.10 atm, though, the gas volume equals only 1.000×10
4
Lat 1 atm.
(1.000 × 10⁴ L) / (5000. L/cylinder) = 2.00 cylinders.
5000L
1.000×10
4
L
/cylinder =2 cylinders
