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A physicist drives through a stop light. When he is pulled over, he tells the police officer that the Doppler shift made the red light of wavelength 635 nm appear green to him, with a wavelength of 510 nm. The police officer writes out a traffic citation for speeding. How fast was the physicist traveling, according to his own testimony

Respuesta :

Answer:

[tex]6.59\times 10^7m/s[/tex]

Explanation:

We are given that

Wavelength of red light=[tex]\lambda=635nm[/tex]

Wavelength of  green light=[tex]\lambda'=510 nm[/tex]

We have to find the speed of physicist traveling according to his own testimony.

We know that

[tex]\frac{\lambda}{\lambda'}=\sqrt{\frac{1+\frac{v}{c}}{1-\frac{v}{c}}}[/tex]

Where [tex]c=3\times 10^8m/s[/tex]

Substitute the values

[tex]\frac{635}{510}=\sqrt{\frac{1+\frac{v}{c}}{1-\frac{v}{c}}}[/tex]

[tex]1.25=\sqrt{\frac{1+\frac{v}{c}}{1-\frac{v}{c}}}[/tex]

Squaring on both sides

[tex]1.5625=\frac{1+\frac{v}{c}}{1-\frac{v}{c}}[/tex]

[tex]1.5625-1.5625\frac{v}{c}=1+\frac{v}{c}[/tex]

[tex]1.5625-1=\frac{v}{c}+1.5625\frac{v}{c}=\frac{v}{c}(1+1.5625)[/tex]

[tex]0.5625=2.5625\frac{v}{c}[/tex]

[tex]v=\frac{0.5625c}{2.5625}=\frac{0.5625\times 3\times 10^8}{2.5625}[/tex]

[tex]v=6.59\times 10^7m/s[/tex]