Answer:
1000 N
Explanation:
The Electric Force between two charged particles with charges q1 and q2 respectively, separated by a distance, d, is given as:
F = (k * q1 * q2) / d²
Where k = Coulombs constant
From the question:
Charge of first particle = charge of second particle = q = +1 C
Distance between both particles, d = 3000 m
Therefore, Electric Force is:
F = (9 * 10^9 * 1 * 1) / (3000²)
F = (9 * 10^9) / (9 * 10^6)
F = 1 * 10^3 N = 1000 N
The electric force between both charges is 1000 N.
Answer:
1000 N
Explanation:
The electric force between two charges is given as
F = kq'q/r²......................... Equation 1
Where F = electric force between the charges, q' = magnitude of the first charge, q = magnitude of the second charge, r = distance between the charges, k = coulombs constant
Given: q' = q = 1 C, r = 3000 m, k = 9×10⁹ Nm²/kg²
Substitute into equation 2
F = 1²×(9×10⁹)/3000²
F = 1000 N.
Hence the magnitude of the electric force between them = 1000 N
