Answer:
the person above me is correct, it is 34.0, i had this equation on Savvas Realize
Step-by-step explanation:
mark the person above me brainliest
A cylinder is a three-dimensional structure. The weight of the bushing is 47.4652 pounds.
A cylinder is a three-dimensional structure formed by two parallel circular bases connected by a curving surface. The circular bases' centers overlap each other to form a right cylinder.
The volume of a hollow cylinder is given by the formula,
[tex]\text{Volume of the hollow cylinder}= \dfrac{\pi}{4} (D^2 - d^2)h[/tex]
Therefore, substitute the values,
[tex]\text{Volume of the hollow cylinder}= \dfrac{\pi}{4} (6^2 - (\frac{11}4)^2) \times 7.5\\\\[/tex]
[tex]= \dfrac{3.14}{4} \times (36 - \frac{121}{16}) \times 7.5\\\\= 167.4257\rm\ in^3[/tex]
Now, the weight density of the material is given therefore, the weight of the hollow bushing will be,
Weight = Weight Density × Volume
Weight =0.2835 × 167.4257 in³
= 47.4652 pounds
Hence, the weight of the bushing is 47.4652 pounds.
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