Aidenroseboro
contestada

Stan's heart rate, in beats per minute, was measured 20 times at random. The results are 82, 84, 98, 112, 97, 93, 91, 87, 112, 87, 79, 80, 72, 82, 94, 89, 89, 74, 80, and 72 beats per minute. Construct a 99% confidence interval for Stan's mean heart rate. (82.5659, 92.8341) (80.4942, 92.8341) (82.5659, 94.9052) (82.4288, 92.9712) (80.4942, 94.9052)

Respuesta :

MathPhys

Answer:

(80.4942, 94.9052)

Step-by-step explanation:

The sample mean is x = 87.7.

The sample standard deviation is s = 11.26.

At 99% confidence and 19 degrees of freedom, the critical value is t = 2.861.

The confidence interval is:

x ± t (s/√n)

87.7 ± 2.861 (11.26 / √20)

87.7 ± 7.2053

(80.4947, 94.9053)

The value of  confidence interval at 99% is (80.4942 , 94.9052) ,  Option D is the correct answer.

What is Mean ?

Mean is the measure of Central Tendency of the data set , It is measure by taking the sum of the data set and then dividing by the number of data.

It is given that

The sample mean is

= ∑( 82, 84, 98, 112, 97, 93, 91, 87, 112, 87, 79, 80, 72, 82, 94, 89, 89, 74, 80, 72 ) / 20

x = 87.7.

The sample standard deviation is

s = 11.26

It is asked to determine the confidence interval at 99% confidence

the critical value is t = 2.861.

n = 20

The confidence interval is given by

x ± t (s/√n)

Substituting the values in the equation

87.7 ± 2.861 (11.26 / √20)

87.7 ± 7.2052

80.4942 , 94.9052

Therefore the value of  confidence interval at 99% is (80.4942 , 94.9052) ,  Option D is the correct answer.

To know more about Mean

https://brainly.com/question/521501

#SPJ2

Otras preguntas