Answer:
Volume of water
Initial temperature of the solution
Final temperature of the solution
Mass of NH₄Cl
Explanation:
There are two heat transfers involved in this experiment.
Heat of solution of NH₄Cl + heat lost by water = 0
q₁ + q₂ = 0
nΔH + mCΔT = 0
nΔH = -mCΔT
ΔH = -mCΔT/n
So, you must measure
You will probably assume that the specific heat capacity of the solution is the same as that of water, so you won't be measuring it.