Answer:
2 mole of Sodium hydroxide reacts with 1 mole of Sulfuric acid
Explanation:
Write down the equation in the beginning with reactants and products:
NaOH + H₂SO₄ → Na₂SO₄ + H₂0
Now try to balance it. Try with Na first:
2NaOH + H₂SO₄ → Na₂SO₄ + H₂0
Na atoms are balanced. There are 6 Oxygen atoms on the right and 5 on the left. Balance by increasing the H₂O moles:
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂0
Check if H atoms are also balanced. They are. That means our final reaction is:
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂0
2 Moles of NaOH reacts with 1 mole of H₂SO₄
The moles of sodium hydroxide required to neutralize 1 mole of sulfuric acid have been 2 mol.
The balanced chemical equation for the titration of sodium hydroxide against sulfuric acid has been:
[tex]\rm 2\;NaOH\;+\;H_2SO_4\;\rightarrow\;Na_2SO_4\;+\;2\;H_2O[/tex]
From the balanced chemical equation, for the titration of 1 mole of sulfuric acid, 2 moles of sodium hydroxide has been required.
The moles of sodium hydroxide required for the titration of sulfuric acid has been:
[tex]\rm 1\;mol\;H_2SO_4=2\;mol\;NaOH[/tex]
Thus, the neutralization of 1 mole of sulfuric acid has been required 2 mol of sodium hydroxide.
For more information about titration, refer to the link:
https://brainly.com/question/25485091
