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Find the radius and center of the circle given by the equation below. (x – 6)2 + (y + 4)2 = 7 r = √7 and center at (-4, 6) r = 7 and center at (6, -4) r = 7 and center at (-6, 4) r = √7 and (6, -4)

Respuesta :

Answer:

r = [tex]\sqrt{7}[/tex], centre = (6, - 4 )

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

with (h, k) the coordinates of the centre and r the radius

(x - 6)² + (y + 4)² = 7 ← is in standard form

with centre = (6, - 4) and r² = 7 , hence r = [tex]\sqrt{7[/tex]

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