Answer:
Explanation:
Focal length f = - 4 cm
Object distance u = - 10 cm
v , image distance = ?
Mirror formula
[tex]\frac{1}{v} +\frac{1}{u} = \frac{1}{f}[/tex]
Putting the given values
[tex]\frac{1}{v} - \frac{1}{10} = - \frac{1}{4}[/tex]
[tex]\frac{1}{v}= - \frac{3}{20}[/tex]
v = - 6.67 cm .
magnification
m = v / u
= - 6.67 / - 10
= .667
so image will be smaller in size in comparison with size of object .
Characteristics will be that ,
1 ) it will be inverted and
2 ) it will be real image .
