Answer: The moles of nitrogen dioxide produced are 96.3
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar volume}}=\frac{3714L}{22.4L}=165.8moles[/tex]
[tex]4NH_3(g)+7O_2(g)\rightarrow 4NO_2(g)+6H_2O(g)[/tex]
According to stoichiometry:
7 moles of oxygen [tex](O_2)[/tex] produce = 4 moles of nitrogen dioxide [tex](NO_2)[/tex]
Thus 168.5 moles of oxygen [tex](O_2)[/tex] will produce = [tex]\frac{4}{7}\times 168.5=96.3[/tex] moles of nitrogen dioxide [tex](NO_2)[/tex]
