One method used commercially to peel potatoes is to soak them in a solution of NaOH for a short time and then remove them from the NaOH. The peel will have separated from the potato and so it can then easily be sprayed off to yield beautifully peeled potatoes! The NaOH solution however, must be analyzed periodically to make sure its concentration is adequate for the reaction In one such analysis, 45.7 mL of 0.500 M H2SO4 is required to react completely with a 20.0 mL sample of the NaOH solution. The products of the reaction are Na2SO4 and water. What is the concentration of the starting NaOH solution?a. 1.14 M b. 2.28 M c. 0.438 M d. 0.500 M e. 0.571M

To solve the concentration of NaOH we need to find the moles of H2SO4. Using the chemical equation we can find the moles of NaOH that react and with the volume the molar concentration as follows:

Moles H2SO4:

45.7mL = 0.0457L * (0.500mol/L) = 0.02285 moles H2SO4

Moles NaOH:

0.02285 moles H2SO4 * (2moles NaOH / 1 mol H2SO4) = 0.0457moles NaOH

Molarity NaOH:

0.0457moles NaOH / 0.020L =

2.28M

Right option:

b. 2.28 M

throwdolbeau throwdolbeau · Answer 2 · 2022-03-04T13:03:00+01:00

The concentration of the starting NaOH solution is:

b. 2.28 M

Neutralization reaction:

The reaction of neutralization of NaOH with H₂SO₄ is:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

Calculation for concentration of NaOH:

We need to find the moles of H₂SO₄. Using the chemical equation we can find the moles of NaOH.

Moles of H₂SO₄:

45.7mL = 0.0457L * (0.500mol/L) = 0.02285 moles of H₂SO₄

Moles of NaOH:

0.02285 moles H₂SO₄ * (2moles NaOH / 1 mol H₂SO₄) = 0.0457moles NaOH

Molarity of NaOH:

0.0457moles NaOH / 0.020L =2.28M

Thus, the concentration of the starting NaOH solution is: 2.28 M.

Find more information about Molarity here:

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