Answer:
2 g
Explanation:
From the question given above, the following data were obtained:
Original amount (N₀) = 16 g
Time (t) = 21.6 s
Amount remaining (N) =?
Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:
Time (t) = 21.6 s
Half-life (t½) of ¹⁶N = 7.13 s
Number of half-lives (n) =?
n = t / t½
n = 21.6 / 7.13
n = 3
Finally, we shall determine the amount of ¹⁶N remaining. This can be obtained as follow:
Original amount (N₀) = 16 g
Number of half-lives (n) = 3
Amount remaining (N) =?
N = 1/2ⁿ × N₀
N = 1/2³ × 16
N = 1/8 × 16
N = 2 g
Thus, the amount of ¹⁶N remaining is 2 g
