Respuesta :
Answer:
Solution given:
(x1,y1)=(-2,3)
(x2,y2)=(1,9)
we have
equation of line
(y-y1)=[tex] \frac{y2-y1}{x2-x1} [/tex](x-x1)
(y-3)=[tex] \frac{9-3}{1+2} [/tex](x+2)
y-3=2x+4
2x-y+4+3=0
2x-y+7=0;is a required equation.
Answer:
Solution given:
(x1,y1)=(-2,3)
(x2,y2)=(1,9)
we have
equation of line
(y-y1)=[tex] \frac{y2-y1}{x2-x1} [/tex](x-x1)
(y-3)=[tex] \frac{9-3}{1+2} [/tex](x+2)
y-3=2x+4
2x-y+4+3=0
2x-y+7=0;is a required equation.