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A large bakery has many different products for sale. Suppose that 200 customers come in between 6 am and 10 am. Of the 200 customers, 140 order donuts, 100 order cinnamon rolls, and 80 order both. Suppose a customer is randomly selected. Find P(no donuts and no cinnamon rolls).

Respuesta :

Using the probability concept, it is found that:

P(no donuts and no cinnamon rolls) = 0.2

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, there are two events.

  • Event A: Customer orders donuts.
  • Event B: Customer orders cinnamon rolls.

Of the 200 customers, 140 order donuts, 100 order cinnamon rolls, and 80 order both, hence:

[tex]A = 140, B = 100, (A \cap B) = 80[/tex]

The number that ordered at least one is:

[tex](A \cup B) = A + B - (A \cap B)[/tex]

[tex](A \cup B) = 140 + 100 - 80[/tex]

[tex](A \cup B) = 160[/tex]

Hence, the number that ordered neither is:

[tex]200 - 160 = 40[/tex]

Then:

[tex]p = \frac{40}{200} = 0.2[/tex]

P(no donuts and no cinnamon rolls) = 0.2

A similar problem is given at https://brainly.com/question/25790531

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