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Secant AD and AE intersect in the exterior of a circle. ∠ BAC measures 27.42° and the measure of DE is 73.18°. Determine the measure of BC .

Secant AD and AE intersect in the exterior of a circle BAC measures 2742 and the measure of DE is 7318 Determine the measure of BC class=

Respuesta :

Answer:

BC = 18.34°

Step-by-step explanation:

The secant- secant angle BAC is half the difference of the intercepted arcs, that is

[tex]\frac{1}{2}[/tex] ( DE - BC) = 27.42

[tex]\frac{1}{2}[/tex] ( 73.18 - BC ) = 27.42 ( multiply both sides by 2 )

73.18 - BC = 54.84 ( subtract 73.18 from both sides )

- BC = - 18.34° ( multiply both sides by - 1 )

BC = 18.34°

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