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One person can do a certain job in ten minutes, and another person can do the same job in fifteen minutes. How many minutes will they take to do the job together?



If x represents how many minutes to do the job together, then how much of the job does the slowest person do?

Respuesta :

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One person can do the job in 10 minutes 

So he can do 1/10th of the job in 1 minute 

Similarly another person can do 1/15th of the job in 1 minute 

Together they can do in 1 minute = 1/10 +1/15 = 5/30 = 1/6th of the job 

So together they can finish the job in 6 minutes. ANSWER 

slowest person does x/ 15 th of the job ANSWER 

1/6 +1/2 +1/3 = 7/6 

together they can do the job in 6/7 days

Answer:

They will take 6 minutes to do the job together.

Slowest person do 2/5 of the total work.

Step-by-step explanation:

Given,

Time taken by first person = 10 minutes,

⇒ One day work of the first person = [tex]\frac{1}{10}[/tex],

While, time taken by second person = 15 minutes,

⇒ One day work of second person = [tex]\frac{1}{15}[/tex],

So, when both persons work together, total one day work =  [tex]\frac{1}{10}+\frac{1}{15}[/tex],

[tex]=\frac{3+2}{30}[/tex]

[tex]=\frac{5}{30}=\frac{1}{6}[/tex]

Thus, the total time taken by the both persons when they work together,

x =[tex]\frac{1}{\frac{1}{6}}[/tex] = 6 minutes

The one who takes more time is slower.

Now, the part of the work done by the slowest person ( second one),

[tex]=\frac{\text{One day work of slowest person}}{\text{Total one day work}}[/tex]

[tex]=\frac{1/15}{1/6}[/tex]

[tex]=\frac{2}{5}[/tex]

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