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a football is kicked vertically upward from a height of 2 feet with an initial speed of 70 feet per seconds.
formula h=2+70t-16t(squared)
describe the balls height above ground (h) in feet(t)seconds ater kicked use the formula to find the balls height 3 seconds after it was kicked

the balls height 3 seconds after kicked was ? feet

Respuesta :

syed514
All you need to do is plug in 3 for t:h=2+70(3)−16(3^2)
and the final answer is 68.
jhonlopera05

Answer:

Height after 3 seconds is 68 ft

Explanation:

Using the given equation

[tex]h=2+70t-16t^2[/tex],

and replacing [tex]t=3[/tex] in it

[tex]h=2+70(3)-16(3)^2[/tex]

[tex]h=68 ft[/tex]

The ball height 3 seconds after kicked it is 68 ft

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