How many grams of silver bromide are produced when 505 grams of cobalt (III) bromide reacts completely in the following equation:
1 CoBr3 + 3 AgNO3 à 3 AgBr + 1 Co(NO3)3
Mass = 473.2 g Explanation: Given data: Mass of cobalt(III) nitrate = 206 g Mass of silver bromide produced = ? Solution: Chemical equation: CoBr₃ + 3AgNO₃ → 3AgBr + Co(NO₃)₃ Number of moles of cobalt(III) nitrate: Number of moles = mass/ molar mass Number of moles = 206 g/ 245 g/mol Number of moles = 0.84 mol Now we will compare the moles of cobalt(III) nitrate with silver bromide.
