Answer:
B 5√34 / 34
Step-by-step explanation:
tan ∅ = opp/adj
In quad II
tan ∅ = 5 / (-3)
---------------------
hyp^2 = 5^2 + (-3)^2
hyp^2 =25 + 9 = 34
hyp = √34
---------------------------
sin ∅ = opp/hyp
sin ∅ = 5/√34
Rationalizing
sin ∅ = 5√34 / 34
Consider this equation [tex]tan(\theta)=-5/3[/tex]. if theta is an angle in quadrant II the of [tex]sin \theta = \dfrac{5\sqrt{34}}{{34} }[/tex].
Trigonometric ratios for a right-angled triangle are from the perspective of a particular non-right angle.
In a right-angled triangle, two such angles are there which are not right-angled(not of 90 degrees).
The slanted side is called the hypotenuse.
From the considered angle, the side opposite to it is called perpendicular, and the remaining side will be called the base.
Consider this equation
[tex]tan(\theta)=-5/3[/tex]
B 5√34 / 34
if theta is an angle in quadrant II what is the of sin(theta)
[tex]tan(\theta) = \dfrac{\text{Length of perpendicular}}{\text{Length of base}}[/tex]
In quadrant II
tan ∅ = 5 / (-3)
[tex]hyp^2 = 5^2 + (-3)^2\\hyp^2 =25 + 9 = 34\\hyp = \sqrt{34}[/tex]
[tex]\sin(\theta) = \dfrac{\text{Length of perpendicular}}{\text{Length of Hypotenuse}}[/tex]
[tex]sin \theta = \dfrac{5}{\sqrt{34} }[/tex]
Rationalizing
[tex]sin \theta = \dfrac{5\sqrt{34}}{{34} }[/tex]
Learn more about trigonometric ratios here:
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