Calculate the volume of sulfur dioxide produced when 27.9 mL O2 reacts with carbon disulfide.

Answer:
18.6 ml
Explanation:
From the balanced equation given:
Volume of oxygen = 27.9 mL
From the equation, we will see that three moles of oxygen react with CS_2 to give two moles of sulfur dioxide (SO_2)
Also, three mL of O_2 yields two mL of SO_2
Now, to calculate the volume of SO_2; we have:
[tex]=27.9 mL \times \dfrac{2 mL \ of SO_2}{3 mL \ O_2}[/tex]
= 18.6 mL of SO_2