Answer:
[tex]F_w=1000Hz[/tex]
Explanation:
From the question we are told that:
Frequency [tex]F=1200[/tex]
Speed [tex]V_w= \frac{1}{5}*343=>68.6m/s[/tex]
Where speed of sound [tex]V_s=343m/s[/tex]
Generally the equation for frequency that echo from the cliff wall is mathematically given by
[tex]F_w=\frac{V_s-V_0}{Vs+V_w}*F[/tex]
[tex]F_w=\frac{343-0}{343+68.6}*1200[/tex]
[tex]F_w=1000Hz[/tex]