FT is tangent to OP at T. If FP = 39 and FT = 36, what is PT?
39
T
36
A 20
B. 12
C. 3
D. 15

Answer:
[tex]D) 15[/tex]
Step-by-step explanation:
[tex]39^{2}=36^{2} +PT^{2}[/tex]
[tex]PT^2=39^2-36^2[/tex]
[tex]PT=\sqrt{39^2-36^2}[/tex]
[tex]PT=15[/tex]
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