Answer: the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23
Step-by-step explanation:
Formula for margin of error : [tex]E=\dfrac{z^*\times (Population\ standard\ deviation)}{\sqrt{Sample\ size}}[/tex]
, where z* = Critical z-value.
Given: population standard deviation = 11.5 ounces
Sample size = 20
Z value for 90% confidence level = 1.645
margin of error (E) = [tex]\dfrac{1.645\times11.5}{\sqrt{20}}[/tex]
[tex]\approx4.23[/tex]
Hence, the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23
