Respuesta :
Answer:
solution given:
acceleration (a)=?
initial velocity (u)=3m/s
final velocity (v)=6m/s
distance (s)=90m
we have
v²=u²+2as
substituting value
6²=3²+2*a*90
36=9+180a
36-9=180a
a=25/180
a=0.1388m/s²
Answer:
The acceleration of dog is 0.15 m/s².
Step-by-step explanation:
Given :
- [tex]\small\red\bull[/tex] Initial velocity (u) = 3m/s
- [tex]\small\red\bull[/tex] Final velocity (v) = 6m/s
- [tex]\small\red\bull[/tex] Distance (s) = 90m
To Find :
- [tex]\small\red\bull[/tex] Acceleration (a)
Using Formula :
[tex]\star{\underline{\boxed{\sf{\purple{{v}^{2} = {u}^{2} + 2as}}}}}[/tex]
- [tex]\pink\star[/tex] v = final velocity
- [tex]\pink\star[/tex] u = initial velocity
- [tex]\pink\star[/tex] a = acceleration
- [tex]\pink\star[/tex] s = distance
Solution :
Substituting all the given values in the formula to find acceleration :
[tex]{\longrightarrow{\sf{{v}^{2} = {u}^{2} + 2as}}}[/tex]
[tex]{\longrightarrow{\sf{{6}^{2} = {3}^{2} + 2 \times a \times 90}}}[/tex]
[tex]{\longrightarrow{\sf{{6 \times 6}= {3 \times 3} + 2 a \times 90}}}[/tex]
[tex]{\longrightarrow{\sf{36=9 + 180a}}}[/tex]
[tex]{\longrightarrow{\sf{36 - 9 = 180a}}}[/tex]
[tex]{\longrightarrow{\sf{27 = 180a}}}[/tex]
[tex]{\longrightarrow{\sf{a = \dfrac{27}{180}}}}[/tex]
[tex]{\longrightarrow{\sf{a \approx 0.15}}}[/tex]
[tex]\star{\underline{\boxed{\tt{\red{a \approx 0.15 \: m/s^{2} }}}}}[/tex]
Hence, the acceleration of dog is 0.15 m/s².
[tex]\rule{300}{1.5}[/tex]