Respuesta :

msm555

Answer:

solution given:

acceleration (a)=?

initial velocity (u)=3m/s

final velocity (v)=6m/s

distance (s)=90m

we have

v²=u²+2as

substituting value

6²=3²+2*a*90

36=9+180a

36-9=180a

a=25/180

a=0.1388m/s²

Answer:

The acceleration of dog is 0.15 m/s².

Step-by-step explanation:

Given :

  • [tex]\small\red\bull[/tex] Initial velocity (u) = 3m/s
  • [tex]\small\red\bull[/tex] Final velocity (v) = 6m/s
  • [tex]\small\red\bull[/tex] Distance (s) = 90m

To Find :

  • [tex]\small\red\bull[/tex] Acceleration (a)

Using Formula :

[tex]\star{\underline{\boxed{\sf{\purple{{v}^{2} = {u}^{2} + 2as}}}}}[/tex]

  • [tex]\pink\star[/tex] v = final velocity
  • [tex]\pink\star[/tex] u = initial velocity
  • [tex]\pink\star[/tex] a = acceleration
  • [tex]\pink\star[/tex] s = distance

Solution :

Substituting all the given values in the formula to find acceleration :

[tex]{\longrightarrow{\sf{{v}^{2} = {u}^{2} + 2as}}}[/tex]

[tex]{\longrightarrow{\sf{{6}^{2} = {3}^{2} + 2 \times a \times 90}}}[/tex]

[tex]{\longrightarrow{\sf{{6 \times 6}= {3 \times 3} + 2 a \times 90}}}[/tex]

[tex]{\longrightarrow{\sf{36=9 + 180a}}}[/tex]

[tex]{\longrightarrow{\sf{36 - 9 = 180a}}}[/tex]

[tex]{\longrightarrow{\sf{27 = 180a}}}[/tex]

[tex]{\longrightarrow{\sf{a = \dfrac{27}{180}}}}[/tex]

[tex]{\longrightarrow{\sf{a \approx 0.15}}}[/tex]

[tex]\star{\underline{\boxed{\tt{\red{a \approx 0.15 \: m/s^{2} }}}}}[/tex]

Hence, the acceleration of dog is 0.15 m/s².

[tex]\rule{300}{1.5}[/tex]