bamihaile81
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a girl throws a packet of biscuit to her boy friend 38.4m away. The boy captured the packet 3.2 sec later at the same height from which the girl has thrown it. how fast did the girl throw the packet? ( take g = 10m/s square) ​

Respuesta :

onyebuchinnaji

The speed of the biscuit thrown by the girl is 12 m/s.

The given parameters;

  • horizontal distance traveled by the biscuit, x = 38.4 m
  • time of motion of the biscuit, t = 3.2 s

The speed of the biscuit thrown by the girl is calculated as follows;

[tex]v_x = \frac{X}{t}[/tex]

where;

[tex]v_x[/tex] is the initial horizontal velocity of the biscuit

The initial horizontal velocity of the biscuit is calculated as follows;

[tex]v_x = \frac{38.4}{3.2} \\\\v_x = 12 \ m/s[/tex]

Thus, the speed of the biscuit thrown by the girl is 12 m/s.

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