Slove for x to the nearest tenth

Step-by-step explanation:
Let me start off by saying that 1 unit side is absolutely useless.
You can translate the 6 unit side downwards, so now we have a right isosceles triangle of 2 equal sides which are 6
The hypotenuse is given here by x.
Applying the Pythagorean theorem i can then say;
[tex]x {}^{2} = 6 {}^{2} + 6 {}^{2} [/tex]
[tex]x {}^{2} = 36 + 36[/tex]
[tex]x {}^{2} = 72[/tex]
[tex]x = \sqrt{72} = 6 \sqrt{2} = 8.485[/tex]
x=8.5
rounded to the nearest 10 :)