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a slender rod of mass m and length l is released from rest in a horizontal position. what is the rod's angular velocity when it has rotated through 90

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Answer:

M g H / 2 = M g L / 2      initial potential energy of rod

I ω^2 / 2 = 1/3 M L^2 * ω^2 / 2   kinetic energy attained by rod

M g L / 2 = 1/3 M L^2 * ω^2 / 2

g = 3 L ω^2

ω = (g / (3 L))^1/2

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