Flying against the wind, an airplane travels 2520 kilometers in 4 hours. Flying with the wind, the same plane travels 9450 kilometers in 9 hours. What is the rate of the plane in still air and what is the rate of the wind?

Respuesta :

Using the relation between velocity, distance and time, it is found that:

  • The rate of the plane is of 840 km/h.
  • The rate of the wind is of 210 km/h.

What is the relation between velocity, distance and time?

Velocity is distance divided by time, that is:

[tex]v = \frac{d}[t}[/tex]

Flying against the wind, an airplane travels 2520 kilometers in 4 hours, that is:

[tex]v - v_w = \frac{2520}{4}[/tex]

[tex]v - v_w = 630[/tex]

[tex]v = 630 + v_w[/tex]

Flying with the wind, the same plane travels 9450 kilometers in 9 hours, hence:

[tex]v + v_w = \frac{9450}{9}[/tex]

[tex]v + v_w = 1050[/tex]

[tex]v = 1050 - v_w[/tex]

Hence, solving for the wind's speed:

[tex]630 + v_w = 1050 - v_w[/tex]

[tex]2v_w = 420[/tex]

[tex]v_w = \frac{420}{2}[/tex]

[tex]v_w = 210[/tex]

For the plane, we have that:

v = 1050 - 210 = 840.

More can be learned about the relation between velocity, distance and time at https://brainly.com/question/24316569

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