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Imagine we are throwing a loaded die (6 sides). The probability that the die shows a 6 is twice as high as the probability of each of the other numbers. On average, out of these 70 throws how many times would the die show the number 6

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Probability

It is a branch of mathematics that deals with the occurance of a random event. The value is expressed from 0 to 1. It predicts how likely events are to be happened .

Step by step solution:

Die has six sides so probability of each is [tex]\frac{1}{6}[/tex] but,

The probability that the die shows a 6 is twice as high as the probability of each of the other numbers.

so,

the probability of 6 is [tex]\frac{2}{7}[/tex] and others probability is [tex]\frac{1}{7}[/tex]

we throw die 70 times

so probability 6 out of 70 throws is

70×[tex]\frac{2}{7}[/tex]

=20              

out of these 70 throws , the probability of die showing number six is 20 times.

Learn more about Probability:

brainly.com/question/13604758

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