What can you say about the y-values of the two functions f(x) = 3x² -3 and
g(x) = 2* - 3?
A. g(x) has the smallest possible y-value.
B. The minimum y-value of g(x) approaches -3.
C. f(x) and g(x) have equivalent minimum y-values.
D. f(x) has the smallest possible y-value.

Respuesta :

The y-values of the two functions f(x) = 3x² -3 and g(x) = 2* - 3 has the minimum y-value of g(x) approaches -3 and f(x) contains the smallest possible y-value.

What is a function?

It exists described as a special kind of relationship and they contain a predefined domain and range according to the function every value in the domain exists connected to just one value in the range.

Given: f(x) = 3x² -3

As we can see in the graph the first term exists 3x² and exists still positive for all x.

The range for f(x) ∈ [-3, ∞)

When x = 0 then f(x) = -3

The above value exists as the smallest possible value on the y-axis.

Given:  [tex]g(x) = 2^x - 3[/tex]

[tex]2^x[/tex] exists also a positive quantity and it exists as an exponential function.

The range for the g(x) ∈ (-3, ∞)

It signifies that g(x) never touches the y-axis at -3.

We can express the minimum value of g(x) approaches -3.

Therefore, the correct answer is option B. The minimum y-value of g(x) approaches -3 and option D. f(x) has the smallest possible y-value.

To learn more about functions refer to:

https://brainly.com/question/17002947

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