The density of proton exists [tex]1.7*10^{-24}/2 * 10^{-26}cm^3[/tex].
Given:
[tex]$r = 2 * 10^{-26[/tex] units.
[tex]mass = 1.7 * 10^{-24[/tex] grams
Formula, V [tex]= 4/3 * \pi * r^3[/tex]
Density = mass / Velocity
Put the givens into the formula.
Find the value for [tex]r^3[/tex]
[tex]V = (4/3) 3.14 * (1 * 10^{-13})^3[/tex]
To estimate the volume indicate divide by 3
[tex]V = (4/3) 3.14 * 1 * 10^{-39[/tex]
[tex]V = 1.256 10^{-38/3[/tex]
[tex]V = 4.1867 * 10^{-39[/tex]
Density = mass / velocity
Density = [tex]1.7*10^{-24}/2 * 10^{-26}cm^3[/tex].
Therefore, the density of proton exists [tex]1.7*10^{-24}/2 * 10^{-26}cm^3[/tex].
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