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A boat is heading towards a lighthouse, whose beacon-light is 113 feet above the
water. The boat's crew measures the angle of elevation to the beacon, 7°. What is the
ship's horizontal distance from the lighthouse and the shore)? Round your answer to
the nearest tenth of a foot if necessary.

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We conclude that the horizontal distance between the ship and the lighthouse is 920.3 feet.

How to find the ship's horizontal distance from the ship to the lighthouse?

We can use trigonometry to solve this. We know that the height of the lighthouse is 113 ft, and that the angle of elevation when seen from the ship is 7°.

Then we have a right triangle where we know that one angle measures 7° and the opposite cathetus to this angle measures 113 feet, and we want to find the adjacent cathetus, then we can use the tangent relation.

tan(7°) = 113ft/x

Where x is the opposite cathetus, which is the horizontal distance we want to find.

x = 113ft/tan(7°) = 920.3ft

We conclude that the horizontal distance between the ship and the lighthouse is 920.3 feet.

If you want to learn more about right triangles.

https://brainly.com/question/2217700

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