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Find the mass of water that has a specific heat of 4.18J/g C that requires 1500 J of energy to go from 33 to 113C

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CintiaSalazar

Taking into account the definition of calorimetry, the mass of water is 4.4856 grams.

Calorimetry

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

  • Q is the heat exchanged by a body of mass m.
  • c is the specific heat substance.
  • ΔT is the temperature variation.

Mass of water

In this case, you know:

  • Q= 1500 J
  • c= 4.18 [tex]\frac{J}{gC}[/tex]
  • m= ?
  • ΔT= 113 C - 33 C= 80 C

Replacing in the definition to calculate heat exchanges:

1500 J = 4.18 [tex]\frac{J}{gC}[/tex]× m× 80 C

Solving:

1500 J = 334.4 [tex]\frac{J}{g}[/tex]× m

1500 J÷ 334.4 [tex]\frac{J}{g}[/tex]= m

4.4856 g= m

Finally, the mass of water is 4.4856 grams.

Learn more about calorimetry:

brainly.com/question/11586486

brainly.com/question/24724338

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